About cookies on this site Our websites require some cookies to function properly (required). In addition, other cookies may be used with your consent to analyze site usage, improve the user experience and for advertising. For more information, please review your options. By visiting our website, you agree to our processing of information as described in IBM’sprivacy statement. To provide a smooth navigation, your cookie preferences will be shared across the IBM web domains listed here.
September 2014
ln(2^3^4^5)=3^1024 * ln(2)
We need to compute the fraction part of 3^1024 * ln(2).
The Taylor series of ln(x) around 1 converges slowly, so to compute ln(2) one can compute ln(1/2) = -ln(2), which converges much faster; but to earn a star we use the following relation:
ln(2) = ln(4/3)-ln(2/3)
which gives us the series
ln(2) = 2*sum_{i_0}^\infty 3^{-2i-1}\over(2i+1}
3^1024 has 489 digits, so we need to compute ln(2) with ~500 digits accuracy, but using the above formula we can see that ~550 terms would suffice, since the contribution of the rest to 3^1024 ln(2) is much smaller than 10^-10. So we get that the fractional part is: 0.4261674320657868...
The answer is the exponent of the above: 1.53137715531...
If you have any problems you think we might enjoy, please send them in. All replies should be sent to: ponder@il.ibm.com