June 2004 - Solution

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June 2004 Challenge


ANSWER:

If our N points are equally spaced along the main diagonal: (i/N, i/N) for i=0,1,...,N-1, then any solution will have area at most (N(N+1)/2)/(N*N) = (N+1)/(2*N), which is slightly larger than 1/2. But a general solution is not known.